The Prime factorisation of a number is 2^4 X 3^5 X 7^2 X 11.

Write down 3 factors of the number that are greater than 100.

To find the answer, we need to simplify the index notation further so that we get something like this:16x243x49x11=2095632

Then we multiple the factors:16x11=176

we then test this number 2095632/176=11907 this means that 176 and 11907 are a factor of 2095632 and they are more than 100

since 243 is a number more than 100, lets try it 2095632/243=8624

this proves to us that 243 and 8624 are a factor of 2095632.

The answer is 176,11907 and 243

Pg 9 #25 & textbook p9 #26

The Prime factorisation of two numbers are 2 X 3^2 X 7^3 X 13 and3 X 7^2 X 13^3 X 17 .

Write down 3 common factors of the numbers.

First we extend the index notation

1)2x3x3x7x7x7x13=11466

2)3x7x7x13x13x13x17=5490303

Next we find the common numbers:3,7,13

Then we multiply the numbers 3x7x13=273. this is the HCF

Every number,except 0,has one common factor the no. 1.

11466 and 5490303 can be divided by 3

the answer is 273,1 and 3