tag:blogger.com,1999:blog-8223614157673075832.post306075724283846551..comments2010-01-24T21:55:36.538+08:00Comments on My Journey Begins at...SST: Maths Homework-prime numbers continued textbookHarsh Sethhttp://www.blogger.com/profile/05202962309858589409noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-8223614157673075832.post-7624265038275684492010-01-24T21:55:36.538+08:002010-01-24T21:55:36.538+08:00Harsh
Textbook Pg 9 #25:
That's very good rea...Harsh<br /><br />Textbook Pg 9 #25:<br />That's very good reasoning :D<br /><br />Indeed, using the prime factors expressed in the index notation, we could multiply different 'combinations' of factors to result a larger factor (as required in the question).<br />Indeed, apart from using the final number (2095632) to check your factor, you have rightly pointed out that the number resulted through checking is another factor for the number, too :D<br /><br />Textbook p9 #26:<br />Indeed, you already found the 3 factors to the 2 numbers (3, 7 and 13). <br />Interestingly, you didn't forget "1".<br /><br />You are also right that the HCF is another factor :D <br />However, if you check amongst the 2 numbers, the HCF should be 3 x 7^2 x 13.Loh Kwai Yinhttps://www.blogger.com/profile/09629206529240771085noreply@blogger.com